JavaScript/Notes/Scope

Scope Chain and Identifier Resolution.

From global object property access.

I am currently seeing some weird behavior with the global object: <source lang="javascript"> console.log(window.foo); // this returns undefined console.log(this.foo); // this returns undefined console.log(foo); // this is a reference error </source>

The Mozilla docs on Reference error simply state:

A ReferenceError is thrown when trying to dereference a variable that has not been declared.

I realize accessing a non existent property on an object should return undefined... which accounts for the first two cases... but whats going on in the third case?

As expected, getting a property off an object, the prototype chain is searched. When that happens, if the property is not found, then `undefined` results.

But with scope chain resolution, when the property is not resolved, an error results.

| 11.1.2 Identifier Reference | An Identifier is evaluated by performing Identifier Resolution | as specified in 10.3.1. The result of evaluating an Identifier | is always a value of type Reference.

...

| 10.3.1 Identifier Resolution | Identifier resolution is the process of determining the binding of an | Identifier using the `LexicalEnvironment` of the running execution context.

> console.log(foo); // this is a reference error >

Identifier `foo` is resolved to a Reference with null as the base object. In ES5, it looks as if it is a Reference with base object as `undefined`. With either spec, the result will be the same: `ReferenceError`. ES5 gets a little fancy with the explanation.

> The Mozilla docs on Reference error simply state: > > A ReferenceError is thrown when trying to dereference a variable that > has not been declared. >

They mean that when you try and get the value of an Identifier in a PrimaryExpression and the Identifier is not resolved, then the base object is null (or now `undefined`) that the attempt to get at the value is going to result in a ReferenceError.

So when you have an Expression like:

console.log(foo);

or even just a PrimaryExpression:

foo // a PrimaryExpression.

Identifier `foo` must be first resolved. The base object for that value is null (or so"undefined") and the when the expression is evaluated, it tries to get the value, and then finds the base object is null and throws a ReferenceError is thrown.

| 8.7.1 GetValue (V) | | 1. If Type(V) is not Reference, return V. | 2. Let base be the result of calling GetBase(V). | 3. If IsUnresolvableReference(V), throw a ReferenceError exception.

...

| IsUnresolvableReference(V). Returns true if the base value | is undefined and false otherwise.

The MDC docs might not say it, and you didn't ask, either, but in strict code, assignment to undeclared Identifier will result in referenceerror too.

> I realize accessing a non existent property on an object should return > undefined... which accounts for the first two cases... but whats going > on in the third case?

An Identifier resolution was performed on the scope chain. Just remember the difference when getting a property fails: With object properties - the prototype chain is used and the result is undefined. With unqualified Identifiers, the scope chain is searched in the result is ReferenceError.

Omitting var in VariableDeclaration

Assignment without var is not a variable declaration.

| `foo = 1;`

The identifier foo must be resolved up the scope chain (see 11.13.1 Simple Assignment, also below). If foo is not found, a foo property is created on the global object (see 8.7.2 PutValue).

| 11.13.1 Simple Assignment (= ) | The production AssignmentExpression : LeftHandSideExpression = | AssignmentExpression is evaluated as follows: | 1. Evaluate LeftHandSideExpression. | 2. Evaluate AssignmentExpression. | 3.Call GetValue(Result(2)). | 4.Call PutValue(Result(1), Result(3)). | 5.Return Result(3).

Step 4 leads to PutValue(foo, 1);

| 8.7.2 PutValue(V, W) | 1. If Type(V) is not Reference, throw a ReferenceError exception. | 2. Call GetBase(V). | 3. If Result(2) is null, go to step 6. | 4. Call the Put method of Result(2), passing GetPropertyName(V) | for the property name and W for the value. | 5. Return. | 6. Call the Put method for the global object, passing | GetPropertyName(V) for the property name and W for the value. | 7. Return.

Step 2, GetBase(v) is null, so that leads to step 6. That leads to Put(foo, 1) on the global object.

| 8.6.2.2 Put(P, V) | When the Put method of O is called with property P and value V, | the following steps are taken: | 1. Call the CanPut method of O with name P. | 2. If Result(1) is false, return. | 3. If O doesn't have a property with name P, go to step 6. | 4. Set the value of the property to V. The attributes of the | property are not changed. | 5. Return. | 6. Create a property with name P, set its value to V and give it | empty attributes. | 7. Return. | Note, however, that if O is an Array object, it has a more elaborate | Put method (15.4.5.1).

Note step 6: Create a property with name P, set its value to V and give it empty attributes.

Global object properties (user-defined ones, at least) are Deletable, variables, global or otherwise, are not.